$-2x-5=7$
$6.28\cdot300$
$7x^2-2x+4=0$
$\lim_{x\to\infty}\left(\frac{2x^2-\:x+3}{x^3\:-\:8x+\:5}\right)$
$\left(x^2+5y\right)^4$
$\left(\frac{3}{2}x+3\right)\left(\frac{3}{2}x-3\right)$
$\left(-17\right)\cdot\left(-6\right)$
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