$4a+5=2+3.25a$
$2m^2n+7mn^2+3n^3$
$\left(2+3x\right)\left(5-4x\right)$
$5\left(-22\right)\:=\:$
$\lim_{x\to\infty}\left(\frac{3x^2-1}{2-3x}\right)$
$\left(8x^3-12x^2+6x-1\right)+\left(8x^3+12x^2+6x+1\right)$
$4+-3\left(n+2\right)$
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