$\frac{x^4}{\left(x^2-1\right)^2}$
$\left(3a+8\right)\left(3a+4\right)$
$13=m-7$
$x^2+1<2x$
$\left(a^2-b^2\right)\left(a^5-b^5\right)$
$x\:\frac{dy}{dx}-4y=\:x^3-x$
$\frac{x^6+y^9}{x^2+y^3}$
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