$2+4\cdot6-8$
$3x^2-8x-3x$
$-5x^6+8x^4+7x^3-9x^2$
$\frac{1-a^3b^3}{1-ab}$
$\ln\left(\sqrt{x+40}\right)=3$
$\left(x-8\right)\left(x^2-3\right)$
$\cos\:\left(-u\right)=\cos\:\left(u\right)$
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