$\frac { \frac { 1 } { x } } { \frac { 1 } { x } }$
$e=\frac{1.\overline{3}+1}{1.6\left(1.83-1\right)}-0,08$
$\int\sqrt{225-x^2}dx$
$\left(5h-\frac{1}{2}k^4\right)\left(5h+\frac{1}{2}k^4\right)\:$
$54x^3-16$
$3x^2-4x+4\:=2$
$\frac{n^2-m^2}{n^2-2mn+m^2}$
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