$\cot\left(x\right)+\tan\left(x\right)=\frac{1+\cot^2\left(x\right)}{\cos\left(x\right)}$
$16\log b\:+\frac{\log b}{2}-64\log b$
$-25y^2-121$
$a^4b^2-c^2$
$-42-\left(-16-14\right)$
$5-\left(-57\right)$
$4+-1+4+-2$
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