$\frac{d}{dx}3xy+x^2=y$
$\left(1-8xy\right)\left(9xy+1\right)$
$\left(4x-9y\right)^2$
$-5\:=\:\frac{c}{6}$
$\left(3x+5\right)\left(3x+7\right)$
$4=b^{\frac{1}{3}}$
$\int\frac{x^3+x-1}{\left(x+1\right)\left(x^2+3x-5\right)}dx$
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