$\sqrt{4\left(2\right)^4-10\left(2\right)+5}$
$x=\frac{6-x}{x}$
$97\cdot83$
$16\:a^2m^3p^6\:+\:28m^5p^2\:-\:8\:a^2mp^6\:\:$
$a+3=5a+11$
$\frac{64m^6-1}{4m-m}$
$\frac{d^2}{dx^2}\left(1-\frac{y^3}{x^2}\right)$
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