$\frac{d}{dx}13e^{6x}$
$\left(8x+5y=47\right)\left(2x-6y=-10\right)$
$6x+4<3x-8$
$a^3+10a^2-24a$
$\left(-5^2\right)^2$
$\left(\frac{x}{9y}+\frac{y}{3x}\right)\cdot\frac{1}{4}$
$\int e^x+5\left(9x+5\right)dx$
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