$\sqrt[5]{\frac{\left(4x+1\right)\left(x+3\right)^2}{\left(x^3+6\right)\left(x+8\right)}}$

$x^2-3x-2$

$\left(\cos\left(2f\right)\right)\left(\frac{-e^{-cf}}{c}\right)$

$\frac{\left(2x-6\right)}{\left(x^2\right)}$

$\int7xe^{3x}dx$

$\frac{\left(1+\cos\left(x\right)\right)\left(1-\cos\left(x\right)\right)}{\tan\left(x\right)^2}$

$26-5.4\ln\left(49\right)$