$\frac{x^2-3x+2}{x-5}$
$\left(3-a^2b\right)\left(3+a^2b\right)$
$3a+2b-\left(c-b-a\right)$
$\frac{2w^{-9}b}{5\left(w^{-5}b^{-4}\right)^2}$
$\left(x+7\right)\left(x+13\right)$
$\lim_{x\to3}\left(\frac{x^2}{x^2-9}\right)$
$x+2y=y$
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