$\frac{\left(1+\cos\left(x\right)\right)}{\sin\left(x\right)}+\tan\left(x\right)=\frac{\left(1+\cos\left(x\right)\right)}{\sin\left(x\right)\cdot\cos\left(x\right)}$

$5p-p+9p-10p+9p-6p$

$x^2-20x+41$

$\left(-14\right)-\left(-5.1\right)$

$16p^2+56pq+49q^2$

$\int\frac{8}{\left(3x-2\right)\left(x^2\right)}dx$

$85cd^4-60c^3d^2+95cd$