$\int_{-4}^6\left(x+6\right)\frac{1}{x^2-4x+8}dx$
$\frac{4}{\sqrt{1-x^2}}$
$\left(x-3y\right)\cdot\left(x+2y\right)$
$-\left(3x-2x^2\right)-\left(x+4x^2\right)$
$x\frac{dy}{dx}-y=xe^x$
$\frac{dy}{dt}=1+\frac{y}{t}$
$10x^2+5+5x$
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