$\lim_{x\to\infty}\left(1+\frac{1}{x}\right)^{\frac{x}{10}}$
$3x+4>0$
$3y-y+1y$
$\left(2+x^2\right)\left(4+x^6\right)$
$\lim\:_{x\to\:6}\left(\frac{x^2-36}{x-6}\right)$
$+8-\infty$
$3x+2;x=0$
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