$\lim_{x\to0}\sin\left(x\right)\ln\cos\left(x\right)$
$\frac{sin\left(x\right)}{\cos\left(x\right)+1}+\frac{sin\left(x\right)}{cos\left(x\right)-1}=-\frac{2}{tan\left(x\right)}$
$\log\:_{10}\left(6x-1\right)-\log\:_{10}\left(x+4\right)=\log\:_{10}\left(x\right)$
$15\le x+2$
$\frac{-2000+4\pi r}{r^2}$
$\left(t-9\right)\left(t-5\right)$
$3x\:+\:1\:\ge\:2x\:-\:3$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!