$\frac{\sin\theta+\tan\theta}{1+\sec\theta}=\sin\theta$
$\int\left(\frac{6x^8}{1+x^2}\right)dx$
$81x^2-36xy+4y^2$
$\lim_{x\to\infty}\left(\frac{3x-6}{3x+1}\right)^{-2x}$
$\int64x^7ln\left(x\right)dx$
$\int\:\:2x^2+3x-1-\left(3x+6\right)dx$
$( 3 x + 6 ) ( 2 x + 4 )$
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