$\lim_{x\to4}\left(\frac{xln\left(4x\right)}{2}\:-\:\frac{x^2}{4}\right)$
$tan\left(\pi-x\right)=-tan\left(x\right)$
$-8x+7<31$
$-8y+12xy-3y$
$18xy+3y$
$\frac{d^2-1}{d+1}$
$\int\left(3x^2\tan\left(y\right)-\frac{2y^3}{x^3}\right)dx$
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