$\left(4x^2+y^2-xy\right)dx=\left(3x^2\right)dy$

$f\left(x\right)=\left(3x^{\frac{1}{3}}+\frac{4}{x^2}\right)\left(\frac{3}{x^{\frac{2}{3}}}-6\right)$

$\left(x-3\right)\left(x+4\right)<0$

$\sqrt{x+2}+x=10$

$x3+27$

$\lim_{x\to10}\left(2x\cdot\log_x\left(3\right)\right)$

$6y=24$