$\frac { 0 } { - 2.80 }$
$xy'-y=xlnx$
$1-\sin\left(\infty\right)\cdot\cos\left(\infty\right)\cdot\tan\left(\infty\right)=\cos\left(\infty\right)^2$
$2\:\left(x\:+\:6\right)\:>x\:+\:20$
$\sqrt[3]{-125x^8y^{15}}$
$\frac{-12x^3y^5}{3xy^3}$
$\frac{\left(11x-3\right)}{x-4}\ge9$
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