$y;\:x=0.125;\:y=0.0001$
$\int\frac{2}{\left(x-1\right)^{2}\left(x^{2}+1\right)}dx$
$\frac{1-\cos\left(a\right)}{1+\cos\left(a\right)}$
$\left(11ab-4c\right)^2$
$y^2+6y+8$
$\frac{4-u}{u^2-u-12}+\frac{u}{u+3}$
$-10x-8=-8\left(6x-5\right)+10\left(2+4x\right)$
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