$\left(2z-\frac{1}{2}\right)^2$
$-\left(28-30\right)-33$
$\frac{\tan\left(a\right)+\cot\left(a\right)}{\sec^2\left(a\right)}$
$\int\left(\cot\left(z\right)\ln\left(\sin\left(z\right)\right)\right)dz$
$9x^3\cdot2x^2y^3$
$-16\::\:-6\:+\:2\:.7$
$3\tan^2x-1=\sec^2x$
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