$25x^6-4y^4$
$\int\frac{x^2-5x+6}{x^2+4}dx$
$\frac{dy}{dt}\:+\:\frac{y}{2}=2+t$
$\left(x^2\:+\:3\right)\left(x^2\:-\:7\right)$
$5\left(5a+z\right)^3$
$\frac{1}{\cot2\theta}+\sec\theta\cos\theta$
$10x^3+25x^2$
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