$\lim_{x\to+\infty}\left(\frac{x^2-1}{x^2-4x+3}\right)$
$7-32-45-6+12-45$
$\left(tan\:a+cot\:a\right)^2=sec^2a+cosec^2a$
$5-\left(3+4\right)-\left(6-5\right)$
$\lim_{x\to-2}\left(\sqrt{\frac{x^2+5x+6}{4+x^2}}\right)$
$2x^2+29x$
$2x^2+6x+64\cdot8-12^212^2$
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