$\frac{x^3-x^2+1}{x^2+4}$
$-2+8+2+17$
$32^2-52+4$
$2\left(\cos\left(3x\right)\cdot\cos\left(x\right)\right)$
$\left(3x-1\right)^2\cdot tan\:4x$
$-9\:+\:\:-5\:\left[-7\:-\left(-3\:x\:4\right)\right]\:+6\:-4$
$\sin3x-2=-3\sin3x$
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