$\left(x+z^2-2ax-2az^2\right)$
$-10x^2+15$
$\int2\sqrt{s}ds$
$h\left(z\right)=\left(4-z^2\right)\left(z^3-z+3\right)$
$\frac{4x^3+3x}{2x-3}$
$\frac{1\:+\:cos\:2u}{2}$
$x^4\left(x^6-1\right).\:x^2$
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