$\frac{a^5b^4c^2}{ab^3c}$
$\left(8y-10a\right)^2$
$18-4\:x\:3\:-2$
$\frac{2a^5+a^3+5a-8}{a+1}$
$\sin^4a-\cos^4a=1-2\cos^2a$
$204+200$
$3a^2;\:a=1,7$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!