$9\cdot2^6-11\cdot2^5$
$5x^2-40x+15$
$\frac{2^4-4s}{6s^3}$
$\int\:x\:arc\:\sec\left(2x^2\right)dx$
$ab=ba$
$\frac{x^3+3x^2-2x+8}{x+2}$
$\frac{3\sec\:\left(\theta\:\right)+3}{\sec\:^2\left(\theta\:\right)-1}=\frac{3}{\sec\:\left(\theta\:\right)-1}$
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