$6a^2-12a+6$

$\frac{\sec^2\left(x\right)-1}{\sin^2\left(x\right)}=\tan^2\left(x\right)+1$

$\left(5-x\right)\left(2-x\right)-x\left(x-3\right)\le0$

$\frac{\left(1-cos^2x\right)}{sin2x}=\frac{1}{2}tanx$

$8-\frac{-10}{2}$

$\frac{20}{9}+\frac{2}{-9}$

$\frac{d}{dx}2x^3-8x$