$\frac{1}{sin^2\left(x\right)}-1=\frac{1}{tan^2\left(x\right)}$
$\int cos\left(\frac{\theta\:}{2}\right)d\theta\:$
$x^2-16x+100$
$a^3-4$
$57.08-22.22$
$7-9x=34$
$\int\:16sin\left(4x\right)^3cos\left(4x\right)dx$
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