$x^3\left(-2+\frac{7}{x}\right)$
$z^2-6z-72$
$4\left(+x^3-3x^2-144x+440\right)$
$\:6x\left(3x-1\right)^2+2x^2\left(1-3x\right)^2$
$\left(2-x\right)^2\left(4+x^2\right)$
$\frac{\left(-5x^2+9x+2\right)}{x^2-2}$
$3c^{\frac{2}{3}}=27$
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