$\left(x^{10}\right)^3$
$\frac{\left(x^2+6x+9\right)\left(x+1\right)}{\left(x-5\right)}$
$\left(3\right)^2+\left(2^2-12+4\right)^3\cdot2-5$
$x+1\le\frac{1}{2}$
$\lim_{x\to\pi}\left(\frac{\tan\left(x\right)}{1-\cos\left(x\right)}\right)$
$-3a+1\:con\:a$
$5\left(x^2+3y\right)-2\left(4y-x^2\right)$
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