$x\left(x-3\right)\left(x+2\right)$
$4\left(x-1\right)>\left(x^2+9\right)$
$2x^2+5x=-x^2+1$
$-3\left(1\right)\left(-1\right)\left(-2\right)$
$\lim_{x\to0}\left(\frac{sin\left(3x\right)}{x}\right)^2$
$\frac{2}{5}n+6=10$
$5^{x+3}=25^{x-2}$
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