$\frac{5}{6}-\frac{1}{2}=\frac{1}{3}$
$\left(a^3-2y\right)^2$
$\lim_{x\to0}\left(\frac{sen\left(7^{n+1}\right)-24}{n}\right)$
$2\cdot\left(x^2+3\right)-2x\cdot\left(x-3\right)+6\cdot\left(x^2-x-1\right)$
$\left(-2i+1\right)^3$
$5e^{-0}$
$\frac{3x^2+5x-4}{x+3}$
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