$3x^2-6+2x\ge0$
$-\left(-2\right)-\left(-26\right)$
$\int\left(\frac{1}{\left(2x+3\right)^5}\right)dx$
$\int\left(ze^{x^2}\right)dx$
$\left(8x-19y^2\right)\left(8x+19y^2\right)$
$-14x>-3$
$\int\frac{1}{z^3\sqrt{z^2-16}}dz$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!