$4x^2b^4+4a^2b^5+a^2b^6$
$\left(4x-1\right)\left(3x+4\right)$
$b2\:+\:8b\:+\:15\:$
$9a^2+24a-16$
$\frac{dr}{dx}=\frac{r^2+r}{x}$
$4c^2-20cd+25d^2$
$\left(-6\right).5\left(-6\right).9-\left(-6\right).\left(10\right)$
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