$4+8+2$
$\left(7u^3v+4r^4\right)^2$
$900+200+-500$
$-5\cdot\left(-11\right)$
$81-36a+4a^2$
$\lim_{x\to\infty}\left(\frac{3x^3-11}{24x-9}\right)$
$\left(2m^4-n^3\right)\left(2m^4+n^3\right)$
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