$\frac{1}{cos}-1$
$\left(y+4\right)^2=4x$
$x^3-3x^2-13x+15$
$5x-2^2$
$20x^4-72x^2+36$
$x^2\left(y-2\right)-y\left(x+2\right)+3y^3;\:y=3$
$-\cos\left(2x\right)=-\cos\left(x\right)-1$
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