$5x\:-\:12\:>\:3x\:-\:8$
$\int\frac{\sec\left(x\right)\cdot\tan\left(x\right)}{\left(1+\sec\left(x\right)\right)}$
$8\left(y\:+\:1\right)\:-\:3\left(2x\:-\:y\right)\:-\:\left(-4x\:-\:3\right)$
$\tan^2135$
$\int\:\:\frac{x+2}{\left(2x^2-x\right)}dx$
$y=\frac{1}{16}\text{cdot x}^4$
$\frac{4x+2}{5x^2+7}$
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