$\left(\frac{1}{9}x^{-3}y^4\right)\left(\frac{1}{7}x^3y^{-5}\right)$
$\left(\frac{y}{2}+x\right)\left(x-\frac{y}{2}\right)$
$\frac{4x^5-3x^2+x-+1}{2x^3}$
$\frac{h}{4}+9=20$
$\left(q+7\right)^2$
$y'\:+\:2y\:=\:5x+\:5$
$4x-5=15$
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