$0.12=12$
$256x^4-36$
$\frac{dg}{dt}=6\left(1+2g\right)^{\frac{2}{3.0}}$
$x^4-4b^2$
$\left|3\left(-5\right)\left(6\right)\right|$
$\frac{p}{6}\:+\frac{2p}{p}$
$12+15q+3q+\left(-8\right)$
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