$\left(2x^4y^5\right)\left(3x^5y^6\right)\cdot\left(-12x^2y^8\right)\left(2x^7y^5\right)$
$2021x^2+32x-1\cdot6x^3-6x^2-7x-5$
$\frac{x}{6}+\frac{2}{3}=\frac{3}{2}$
$\frac{3x+7}{12}=\frac{4x-11}{15}$
$6a^2+3ab-12ac$
$\left(4x+x^2\right)^3$
$\lim_{x\to3}\sqrt{\frac{y^3-9}{2y^3+7y+3}}$
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