$38^2-32^2$
$5\cdot6\cdot\left(-1\right)$
$\frac{x^4y^{-3}z^{-1}}{x^{-5}y^{-8}z^2}$
$\ln\left(x\right)+\ln\left(x-3\right)=\ln\left(6x\right)$
$5.\left[-16:\left(21-13\right)-3\left(-7+15\right)\right]$
$x-1=x^2-2x+1$
$\lim_{x\to1}\left(\frac{x^2-5x+4}{2x^2+5x-3}\right)$
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