$4.5-29.26$
$\:t\left(x\right)=9\:ln\:x+7$
$x^2-4x+4\le0$
$\frac{x^2-5}{x}$
$\frac{2x-1}{x^2-x}-2$
$\lim_{x\to0}\left(\cos\left(\frac{6}{x}\right)\right)^{x^2}$
$4x\:-\:\left(-19\right)\:=\:\left(-13\right)$
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