$\frac{dy}{dx}=\frac{-y}{2y-x}$
$\sqrt[4]{8a^2b^3}.\sqrt[6]{3a^5b^4}$
$y'-4y=e^{5x}$
$\left(a^x\:-3\:\right)\left(a^x+8\right)$
$x^2\ge25$
$y^8\cdot2^8$
$6sin^2x+7cosx-8=0$
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