$3x^2-12x+1=0$
$\pi+0$
$\lim_{x\to\infty}\left(2-\frac{1}{x}\right)$
$\int2\left(3x^2+2x-5\right)^6\left(3x+1\right)dx$
$2^{0.2}$
$=400+120x-x^2$
$\frac{1}{2x+1}+\frac{1}{2x-1}=\frac{12}{35}$
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