$\int\frac{1}{16+u^2}dx$
$\int\frac{\left(x^3\right)}{\sqrt{x^2-a^2}}dx$
$1+\frac{1}{4}-\frac{169}{4}$
$+48+68+36$
$1+5.\left(x+1\right)<7.\left(x+2\right)$
$32x-8$
$\frac{1}{1+\cot^2a}=\cos^2a$
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