$5x-3\left(2x-1\right)=1-4\left(x-2\right)$
$25x^2-49=0$
$\int\left(\frac{18+12x}{\left(4-9x-3x^2\right)}\right)dx$
$\frac{3x^{3}-12x^{2}-9x+1}{x-5}$
$2\cdot2\sqrt{2}$
$5y-7x+8=0$
$\lim_{x\to\infty}\frac{x-9}{\sqrt{x}-3}$
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