$-16+x=5$
$\lim_{x\to0}\left(\frac{2xe^{-4x+4}}{2x^2+x}\right)$
$3-\frac{x}{8}=-2$
$\lim_{x\to1}\left(\left(x-1\right)\left(ln^2\left(x-1\right)\right)\right)$
$\lim_{x\to1}\left(m^2\right)$
$\int x\left(2+x^{3}\right)^{2}dx$
$128y+58y$
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