$2x+6<3$
$m^2=49$
$\left(11\right)\left(-2\right)\left(3\right)\left(-2\right)$
$\int4x^{\frac{1}{3}}dx$
$x^2-10x+19=0$
$\lim_{x\to0}\left(x^2+1\right)^{\frac{1}{x\cdot\sin\left(x\right)}}$
$-2\left(5+4\right)\left(3-2\right)$
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