$x+\frac{4}{x}=1$
$x^4+x^3-x^2+x$
$\frac{5x^3-3x^2+x}{5-x}$
$f\left(x\right)=\left(3x^2+2\right)^5$
$\sin\left(x\right)\cos\left(-\frac{12}{19}\right)=1$
$\frac{9-x}{7}=y$
$25\:x\:\left(-2\right)$
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