$\int\frac{x^3+x+3}{x^2+2x+1}dx$

$\int\sec^3\left(x\right)\cdot\cot^2\left(x\right)dx$

$\frac{dy}{dx}\left(\frac{\left(x+1\right)\left(x-6\right)}{\left(x-1\right)\left(x+6\right)}\right)$

$6x^2+5x-4=0$

$m-5n=18$

$\frac{d}{dx}\left(\sqrt[3]{\frac{x}{7x+1}}\right)$

$\:5\cdot0,01$